How would you write a function that prints "bar" every 4th time, and "foo" every other time?

Question

Anonymous · Accepted Answer

The simplest way...pass in number and set up a modulator

Vitali · Answer

Sorry
 if ( count == 3) {  //for every 4

monichols · Answer

You can add a while loop to make it run a certain number of times. Be careful in python not to exceed the maximum recursion depth which I believe is around 1000.

count=0
def fooBar():
    global count
    count = count+1
    if count==0:
        print('bar ',count)
        while count < 999:
            return fooBar()
    elif(count%4 == 0):
        print('foo ',count)
        while count < 999:
            return fooBar()
    else:
        print('bar ',count)
        while count < 999:
            return fooBar()
       
fooBar()

monichols · Answer

Why not:

count=0
def fooBar():
    global count
    count = count+1
    if count==0:
        print('bar ',count)
    elif(count%4 == 0):
        print('foo ',count)
    else:
        print('bar ',count)
fooBar()

Vitali · Answer

recursion? 
printFooBar(int count) {
  if ( count == 2) {
     print("Bar");
     count = 0;
  } else {
     print("Foo");
     count = count + 1;
  }
  printFoorbar(count)
}

main() {
  printFoorbar(0);
}

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