Return the second-smallest element of a list.

Question

Mansi Wakharkar · Accepted Answer

This can be done in following ways
- Using collections: Collections.min(list);
- Simple iteration:
       for (int i : array){
            min = min < i ? min : i;
       }

Anonymous · Answer

Put in a max heap, pop the max, the top is now the second max.

Mantej Singh · Answer

#Python3

lst=[8,7,1,2,3,4,5]
sorted(lst)[-2]

#output is 7

Anonymous · Answer

pair a = (v[0]  a.second) continue;
        
        if (*it < a.first)
        {
            a.second = a.first;
            a.first = *it;
        }
        else if (*it < a.second)
        {
            a.second = *it;
        }
    }
    
    return a.second;

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