given an array of integers, find 3 integers that sum to zero

Question

Gregg Leventhal · Accepted Answer

def sum_to_zero(a):
  for i in range(len(a)):
    for j in range(i+1,len(a)):
      for k in range(j+1,len(a)):
        if sum([a[i],a[j],a[k]]) == 0:
          return [a[i],a[j],a[k]]
  return -1

Anonymous · Answer

just search for it on the web

rsingh0604 · Answer

consider A  as array , if sum of three integer(consider a1,a2,a3) is zero means  a1+a2=-a3
for(int i=0;i< A.length;i++) {
   for(int j=0;j< A.length;j++) {
            for(int k=0;k< A.length;k++) {
                if(k!=i && k!=j) {
                 a[i]+a[j]+a[k]=0;
                 break;
            }
     }
 }
if(i!=a.length || j!=a.length|| k!=a.length)
 system.out.println("we found three numbers",+a[i]+" "+b[j]+ " "+c[k]);

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